Question 822808
Let x be the first integer.


So x+2 is the next consecutive even integer


x*(x+2) = 48


x^2 + 2x = 48


x^2 + 2x - 48 = 0


(x+8)(x-6) = 0


x+8 = 0 or x-6 = 0


x = -8 or x = 6


Since we only want positive even integers, this means that we toss out x = -8 and focus on x = 6


x = 6 ----> x+2 = 6+2 = 8


Therefore, the two numbers are <font color="red">6 and 8</font>