Question 69501
{m^(x^3-3X)  (2X)^3  {m^(x^2+4)(6x^4)} 
I have to assume where the 1st bracket ends.
I have to assume the (2x)^3 is NOT part of the 1st exponent.
I have to assume the (6x^4) is NOT part of the 2nd exponent.
----------
IF all those assumptions are correct the problem becomes:

[(m^(x^3-3x))  * (m^(x^2+4))] [((2x)^3)  *  ((6x^4))]

=[m^(x^3+x^2-3x+4)] [(8x^3)(6x^4)]

=[m^(x^3+x^2-3x+4)] [48x^7]

----------------------------
If that is not the answer it's because one or more or
my assumptions was wrong.
----------
Cheers,
Stan H.