Question 822700
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Hi,
If You meant f(x) = 1/(x^2-3), recommend posting that if You wish.
asymptotes {{{  f(x)=1/x^2 -3 }}}: vertical x = 0 , horizontal y = -3
*[tex \large \text{Domain}f(x)\ =\ \left\{x\ \in\ \mathbb{R}\ \ | \ x<0\ or\ x>0}]
*[tex \large\text{Range}f(x)\ =\ \left\{f(x)\ \in\ \mathbb{R}\ \ | \ f(x)> -3}]
{{{drawing(300,300, -6, 6, -6, 6, grid(1), green(line(0,6,0,-6)) ,
graph( 300, 300, -6, 6, -6, 6,0,-3,(1/x^2) - 3))}}}