Question 822657
A number is selected at random from the set of 1,2,3,4,5,6,7,8,9,10. 
Find:
P(even or power of 3) = P(even)+P(pwr of 3) = (5 + 3)/10 = 8/10
---------------------------

P(power of 2 or even) = P(pwr of 2) + P(even)-P(pwr 2 OR even) 
= (4+5-3)/10 = 6/10
---------------------------

P (odd and prime) = 3/10
-----------------------------------

P(even or prime) = P(even)+P(prime)-P(even AND prime) = (5+3-1)/10 = 7/10
-----------------------------------

P(prime given odd) = P(prime AND odd)/P(odd) = (3/10)/(5/10) = 3/5
===============================
Cheers,
Stan H.
===============================