Question 822560
For (-3,0)
we write  0=(-3)^2+b(-3)+C,   So, 3b-c=9........(i)

and for(1,-16),   So b+c=-17......................(ii) 
        

So (i)+(ii) we get b=-2
So put this into equation(ii) we get c=-15
  so ultimetly the equation is:  y=x^2-2x-15.