Question 822507
Find the smallest number θ larger than 11π such that cos θ = -1/2.
Give exact answer.
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arccos(-1/2)=2π/3+2πn,n=integer
2π/3+2πn>11π
2+6n>33
6n>31
n>31/6=5+
n=6
..
{{{2pi/3+2(pi)n=2pi/3+2(pi)6=2pi/3+12pi=(2pi/3)+(36pi/3)=38pi/3}}}

smallest number θ larger than 11π = 38π/3