Question 822492
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3(2x + 3)^2 = 45
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put the quadratic equation into standard form:
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3(2x + 3)^2 = 45
(2x + 3)(2x + 3) = 45/3
4xx + 12x + 9 = 15
4xx + 12x - 6 = 0
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the above quadratic equation is in standard form, with a=4, b=12, and c=-6
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
4 12 -6
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has two real roots (the x-intercepts), which are:
x = 0.436491673
x = -3.43649167
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Solve quadratic equations, quadratic formula:
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Solve systems of linear equations up to 6-equations 6-variables:
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