Question 822241
{{{(y^2/3/x^3/4)^(2/3)}}}
The outer exponent {{{(2/3)}}} should
be applied to the numerator, then the denominator.
So,

{{{ ((y^2)^(2/3)) / ((x^(3/4))^(2/3)) }}}

=

{{{ ((y)^(4/3)) / ((x^(6/12))) }}}
=
{{{ (y^(4/3)) / (x^(1/2)) }}} = {{{ (y^(4/3)) * (x^(-1/2)) }}}