Question 822202
the equation of the line described below written in slope-intercept form the line passing through point ( {{{  0  }}}, {{{  0  }}} ) and parallel to the line whose equation is {{{3x + 2y - 6 = 0}}}

first write {{{3x + 2y - 6 = 0}}} in slope-intercept form


{{{ 2y  = -3x+6}}}

{{{ y  = -(3/2)x+6/2}}}

{{{ y  = -(3/2)x+3}}}

now, find the equation of the line  passing through point ( {{{  0  }}}, {{{  0  }}} ) and parallel to the line whose equation is {{{ y  = -(3/2)x+3}}}


 *[invoke equation_parallel_or_perpendicular "parallel", -3/2, 3, 0 , 0]