Question 822197
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Hi,
line passing through point (0, 4), perpendicular to the line whose equation is y = {{{highlight(-1/1)}}}x 
New Line has slope = 1
  y - 4 ={{{highlight_green(1/1)}}}(x-0)   |point-slope form, {{{y - y[1] = m(x - x[1])}}}
  y-4 = x
   {{{y = x + 4}}}   |standard slope-intercept form for an equation of a line is {{{y = green(m)x + b}}}