Question 822009
given sin theta = 4/5 and is in the 2nd quadrant, find the exact values 
of csc(t) and cos(t)
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Note: In QII x is negative and y is positive.
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If sin(t) = 4/5 y = 4 and r = 5
Then x = sqrt[5^2-4^2] = 3
So x = -3
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Ans: csc(t) = 1/sin = 5/4
cos(t) = x/r = -3/5
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Cheers,
Stan H.