Question 821922
Find the maximum value of the equation: y=-16t^2+80t+2 
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y=-16t^2+80t+2 
y' = -32t + 80 = 0
t = 2.5
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y@(t=2.5) = -16*2.5^2 80*2.5 + 2
= -100 + 200 + 2
= 102