Question 821874
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
Solve the equation:
e^x - 12e^-x - 1 = 0
{{{e^x - 12/e^x - 1 = 0}}}   |Multiplying thru by e^x so as all denominators = 1
  e^(2x) - 12 - e^x = 0
 {{{ e^(2x)  - e^x  -12 = 0}}}
 (e^x - 4)(e^x + 3) = 0   (tossing out negative value for e^x
    e^x = 4
       x = ln(4)