Question 821819
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Hi,
 2x-4y=-1 &   
  y=x-1  
finding the point of Intersection or the 'solution' to this system of EQs
 2x - 4y = -1
 2x - 4(x-1) = -1  |Substituting for y   {{{y = x-1 }}}
    -2x +4 = -1
     -2x = -5
       x = (5/2)  and y = (3/2)  (x-1)
Pt (5/2, 3/2) is the solution for this system of EQs (the lines intersect at that point)
{{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
circle(2.5, 1.5,0.3),
graph( 300, 300, -6, 6, -6, 6,0, x-1, .5x + .25))}}}