Question 821806
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Hi,
What is the ordered pair of the vertex of 
f(x)=x^2+8x+6
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex
f(x)=x^2+8x+6           |Putting into the vertex form by completing the square
f(x)= (x+4)^2 - 16 +6
f(x)= (x+4)^2 - 10     P(-4, -10) is the vertex
{{{drawing(300,300,  -20,20,-20,20,  
 grid(1),
circle(-4, -10,0.6),
circle(0, 6,0.6),
graph( 300, 300, -20,20,-20,20,0,x^2+8x+6 ))}}}