Question 69429
find the equation of a line in standard form for a line that passes through (1,-3) and has a slope of -1/2
When give a point, (x1,y1), and a slope, m, and asked for an equation of the line, use the point-slope formula, {{{highlight(y-y[1]=m(x-x[1]))}}}.
(x1,y1)=(1,-3) and m=-1/2
{{{y-(-3)=(-1/2)(x-1)}}}
The standard form of a line is {{{highlight(Ax+By=C)}}}, where A, B, and C are integers.  Some books require that A be positive.
{{{y+3=(-1/2)(x-1)}}}
{{{2(y+3)=2(-1/2)(x-1)}}}
{{{2y+6=-(x-1)}}}
{{{2y+6=-x+1}}}
{{{x+2y+6=x-x+1}}}
{{{x+2y+6=1}}}
{{{x+2y+6-6=1-6}}}
{{{highlight(x+2y=-5)}}}
Happy Calculating!!!