Question 821762
Let:
x = larger number
y = smaller number
-
{{{x=y+6}}}eq 1

{{{x^2=y^2+132}}}eq 2
-
Solution:
substitute eq 1 to eq 2
{{{(y+6)^2=y^2+132}}}
-
{{{y^2+12y+36=y^2+132}}}
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{{{y^2-y^2+12y=132-36}}}
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{{{12y=96}}}
-divide both sides by 12
{{{highlight (y=8)}}} smaller number
-
{{{x=8+6}}} 
{{{highlight (x=14)}}} larger number