<PRE><B>Question 821663</B>
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f(t)= P*e^(tk)
where:
P = initial value
k = growth or decay factor per unit of time
t = time
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at t=1 hour, f(1) = 400 bacteria
f(1) = 400 = 100*e^k
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400/100 = e^k
4 = e^k
ln(4) = ln( e^k )
ln(4) = k
k = 1.3862944 growth factor per hour
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at t=3 hours, f(3) = ?
f(3) = 100*e^(3k)
f(3) = 100*e^(3k)
f(3) = 100*64
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answer:
at 3 pm expect 6400 bacteria
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