Question 821369
x^2 - 2x + 15, does not have any real roots
Perhaps they meant x^2 - 2x - 15, Which factors to (x-5)(x+3)
then
{{{(10x)/((x-5)(x+3))}}} = {{{A/(x-5)}}} + {{{B/(x+2)}}} = {{{(A(x+2)+B(x-5))/((x-5)(x+2))}}}
denominators are equal, numerators are equal
10x = A(x+2) + B(x-5)
let x = 5 and last expressions drops out
10(5) = A(5+2)
50 = 7A
A = 50/7, not an integer solution so I am not sure what they mean here