Question 821335
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Hi,
 If the mean of a normal distribution is 85 and its standard deviation is 3.5,
 then find the z-score of the data value 90.25
   z = {{{(90.25-85)/3.5 = highlight(1.5)}}}
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, 0,exp(-x^2/2)), blue(line( 1.5,0, 1.5,exp(-1.5^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}