Question 821285
Given a sample size of 64, with sample mean 730 and sample standard deviation 80, we perform the following hypothesis test. 
H0 :µ= 750 
H1:µ< 750
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z(730) = (730-750)/[80/sqrt(64)] = -20*8/80 = -2
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P-value = P(z < -2) = normalcdf(-100,-2) = 0.0228
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What is the conclusion of the test at the &#945;= 0.05level? Explain your answer.
Since the p-value is less than 5%, reject Ho.
The test results do not support Ho.
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Cheers,
Stan H.
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