Question 821234
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Hi,
 {{{ (( a^2 + 3a )/( a^2 + 4a + 3)) / ((a^2 - 9)/( a^2 - 2a - 3)) }}}  
is the same as: 
{{{ (( a^2 + 3a )/( a^2 + 4a + 3))(( a^2 - 2a - 3)/ (a^2 - 9)) }}} 
factoring            
 {{{ (a(cross( a+ 3))/cross(a+3)cross(a+1))(cross(a-3)cross(a+1)/ cross(a-3)(a+3)))}}}  =  {{{highlight(a/(a+3))}}}