Question 821198
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Hi,
A bacteria culture started with 6500 bacteria and increased by 35% in the <u>first 2 hours</u>. 
 6500 + .35(6500) = 6500(1 + .35) = 1.35(6500)
 Q(t)=6500e^(kt) 
1.35(6500) = 6500e^(kt) 
   {{{1.35 = e^(green(2)k)}}}
   ln(1.35)/2 = k = .1501
 {{{ Q(t)=Q[0]e^(.1501t)}}} 
How long does it take for the population to triple in size? {{{Q(t)/Q[0] = 3}}} 
   {{{ 3 = e^(.1501t)}}}
 ln3/.1501 = t 
Note: Always important to use the assignment requirement for the proper amount of decimal points