Question 820889
Find all solutions to the equation over the interval [0,2pie):
sqrt(2)sin3x+1=0
√2sin(3x)+1=0
sin(3x)=-1/√2=-√2/2
3x=5&#960;/4,7&#960;/4 (In quadrants III and IV where sin<0)
x=5&#960;/12,7&#960;/12