Question 821199
Given that cos x = 15/17 and sin x < 0, then csc x = 
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Reference angle in quadrant IV where cos>0, sin<0.
{{{sin(x)=-sqrt(1-cos^2(x))=-sqrt(1-(225/289))=-sqrt(64/289)=-8/17}}}
csc(x)=1/sin(x)=-17/8