Question 820840
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Hi,
line <u>through (-2,0)</u> and perpendicular to 8x-3y=7  
0r {{{y = green(8/3)x  - 7/3}}}  m = {{{8/3}}} |standard slope-intercept form 
new Line:  m = {{{-3/8}}}
lst  {{{y - 0 = (-3/8)(x+2)}}}   |point-slope form, {{{y - y[1] = m(x - x[1])}}}
     y = <sup>-3</sup>&frasl;<sub>8</sub>  x - 6/8
   3x + 8y = -6      |standard form