Question 820715
Log subscript 12 ( v squared +35) = log subscript 12 (-12v -1)
{{{log(12,(v^2+35))=log(12,(-12v-1))}}}
{{{log(12,(v^2+35))-log(12,(-12v-1))=0}}}
{{{log(12,(v^2+35)/(-12v-1))=0}}} 
convert to exponential form: base(12) raised to log of number (0)=(v^2+35)/(-12v-1)
12^0=(v^2+35)/(-12v-1)
(v^2+35)/(-12v-1)=1
v^2+35=-12v-1
v^2+12v+36=0
(v+6)^2=0
v=-6(multiplicity 2)