Question 820420
The average score for all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0. 
Suppose that 36 pro golfers played a famous California golf 
course today. 
Find the probability that the average score of the 36 golfers exceeded 71.
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z(71) = (71-70)/[3/sqrt(36)] = 1/(1/2) = 2
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P(x > 71) = P(z > 2) = 0.0228
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Cheers,
Stan H.
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