Question 820394
Find &#952; for 0° &#8804; &#952; < 360° that satisfies the stated conditions. Round your answer to the nearest hundredth.
sec &#952; = -1.6667, tan &#952; < 0
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sec&#952;=-1.6667=-5/3=-1/cos&#952;
cos&#952;=-3/5
&#952;=126.870&#730;(In quadrants II where sin>0,cos<0,tan<0)