Question 820434
Given sec(theta)=10 and 3pi/2 < or equal to theta < or equal to 2pi, find the exact numerical value of sin(theta)
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theta is in quadrant IV where sin<0
sec(theta)=1/cos(theta)
cos(theta)=1/10
sin(theta)=-&#8730;(1-cos^2(theta))=-&#8730;(1-(1/10)^2)=-&#8730;(1-(1/100))=-&#8730;(99/100)=-&#8730;99/10=-9&#8730;11/10