Question 69312
umber of moose varied inversely as the number of bears and directly as the number of bison. When there were 75 moose, there were 85 bears and 15 Bison. How many bears were there when there were 10 moose and 30 bison?
:
I see this one has reappeared. Last time I tried it I got (what I thought) was an
outrageous answer, but at the risk of looking ridiculous, here is a method:
:
Moose = (Bison/Bears) * k
:
75 = 15k/85: find k
15k = 75 * 85
15k = 6375
k = 6375/15
k = 425
:
"How many bears (b) were there when there were 10 moose and 30 bison?"
10 = (30k)/b
10 = (30*425)/b
10b = 12750
b = 12750/10
b = 1275 bears