Question 820319
the sum of the digits of a number of three digits is 18. 
<pre>
h+t+u = 18
</pre>
if the number is divided by the sum of the ten's and hundred digits the quotient is 38 the remainder is 1. 
<pre>
Dividend = (Quotient)(Divisor) + Remainder

100h+10t+u = 38(t+h) + 1
100h+10t+u = 38t+38h+ 1
 62h-28t+u = 1
</pre>
if 99 is added to the number the digits will be reversed. 
<pre>
100h+10t+u + 99 = 100u+10t+h
        99h-99u = -99
            h-u = -1

Solve the system of three equations in three unknowns:

  h+  t+u = 18
62h-28t+u =  1
  h    -u = -1

Get h=4, t=9, u=5, number = 495

Edwin</pre>