Question 820215
<font face="Courier New" size="+1">
The largest 6 digit number that can be created using the digits 2, 3, 5, 6, 7, and 9 without repetition is:
<pre>

976532

The next is

976523 (swapped positions of the 3 and the 2)

followed by

976352 (swapped positions of the 5 and the 3)
976325 (left the 3 in the 100s position and swapped 5 with 2)
976253 (put the 2 in the 100s posit and the 5 in the 10s posit)
976235 (swapped the 5 and 3 from above -- all possibilities of the low three digits accounted for)
975632 (from the original number, swap 5 and 6)
       (from here, make all possibilities of the new low three digits -- if you need to go that far)
</pre>

Apply the divisibility rule to these.  If none of them work, continue the pattern creating the next largest number and applying the divisibility rule for 11.  The first one you find is the largest that is divisible by 11.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<div style="text-align:center"><a href="http://outcampaign.org/" target="_blank"><img src="http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png" border="0" alt="The Out Campaign: Scarlet Letter of Atheism" width="143" height="122" /></a></div>
</font>