Question 820239
The width of a rectangle is 9 feet less than its length. The area of the rectangle is 90 ft^ . Find the length and width.
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90 = W*L = W*(W + 9)
W^2 + 9W - 90 = 0
(W-6)*(W+15 = 0
W = 6
L = 15
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Or try pairs of factors of 90
1*90
2*45
3*30
etc, until you find 2 that differ by 9