<PRE><B>Question 820173</B>
At 9:00 am a truck leaves the yard traveling west at a rate of 40 mph. At 11:00 am a second truck leaves along the same route, traveling at 50mph. When will the second truck catch up to the first?
--------
1st truck DATA:
rate = 40 mph ; time = x hrs ; distance = r*t = 40x miles
------
2nd truck DATA:
rate = 50 mph ; time = x-2 hrs ; distance = r*t = 50(x-2) miles
---------
Equation:
distance = distance
40x = 50x-100
10x = 100
x = 10 hrs
------
Meeting time:: 9:00AM + 10 hrs = 7:00PM
==============================
Cheers,
Stan H.
----------------------</PRE>