Question 69304
{{{(x+3)(x-5/7)=0}}}  multiplying, we get (use FOIL crutch)

{{{x^2-(5/7)x+3x-(15/7)=0}}} and this equals


{{{x^2-(5/7)x+(21/7)x-(15/7)=0}}} collecting like terms:

{{{x^2+(16/7)x-(15/7)=0}}} multiply each term by 7

{{{7x^2+16x-15=0}}}


Hope this helps-----ptaylor