Question 819992
  <pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
{{{log(8,(1/64))= x}}} 
{{{8^x = 1/64 = 1/(8^2) = 
  8^(-2)}}}, x = -2
{{{log(8,(1/64))= highlight(-2)}}}