Question 819657
For interval [0,90˚]
3 sin 2θ − 5 sin θ = 0
3(2sinθcosθ)-5sinθ=0
6sinθcosθ)-5sinθ=0
sinθ(6cosθ-5)=0
sinθ=0
θ=0
or
6cosθ-5=0
cosθ=5/6
θ≈33.56˚