Question 819373
Find equation for the line:
{{{y=mx+b}}}
{{{b=y-mx}}}
{{{b=y-((8-2)/(3-(-6)))x}}}
{{{b=y-(2/3)x}}}
Pick either point: (3,8),
{{{b=8-(2/3)*3}}}
{{{b=6}}}
Equation is {{{y=(2/3)x+6}}}


Distance between the two points:
Using Distance Formula,
{{{sqrt((8-2)^2+(3-(-6))^2)=sqrt(36+81)}}}
{{{sqrt(117)}}}
{{{3*sqrt(13)}}}


You want a point (x,y) which is distance sqrt(13) away from (-6,2), and another point which is 2*sqrt(13) from (-6,2).  Use distance formula.
Your unknown points begin as (x, (2/3)x+6 ), and you must take results for which {{{x>-6}}} and {{{y>2}}}.

'
continuing this way,
{{{sqrt((x-(-6))^2+(2-((2/3)x+6))^2)=sqrt(13)}}}
Solve for x and find the corresponding y....