Question 819267
<pre><font size=3>
It is not possible to have an *[tex \large x]-intercept = -1, nor is *[tex \large y]-intercept = -2 possible either.

Intercepts are points, and points, in *[tex \large \mathbb{R}^2], are designated by ordered pairs.

Now, if the *[tex \large x]-intercept is the point *[tex \large \left(-1,\,0\right)] and the *[tex \large y]-intercept is the point *[tex \large \left(0,-2\right)], the slope can be determined using the slope formula:

*[tex \large m\ =\ \frac{y_1\ -\ y_2}{x_1\ -\ x_2}] where *[tex \large \left(x_1,\,y_1\right)] and *[tex \large \left(x_1,\,y_1\right)] are two given points on the line in question.

I would hope that the designation of the *[tex \large y]-intercept would be obvious.

</font></pre>