Question 818655
A chemist has a 24L solution that is currently 8% sodium. How much of a second solution, that happens to be 32% sodium, should be added to the first solution in order to make a new solution that is 20% sodium?
.08*24+.32x=.2*(24+x)
1.92+.32x=4.8+.20x
.12x=2.88
x=24