Question 819092
Log sub 5(x + 2) + log sub 5(x – 2) = 1 
Log sub 5(x + 2)(x – 2) = 1 
(x + 2)(x – 2) = 5^1 
(x + 2)(x – 2) = 5
x^2-4 = 5
x^2 = 9
x = {-3, 3}
but the -3 is an extraneous solution, throw it out leaving:
x = 3