Question 818993
Using the Pythagorean Theorem, and having to leave my answers in simplest radical form, how might one do so with a leg of 7, an unknown leg, and a hypotenuse of 16? 
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x^2 + 7^2 = 16^2
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x^2 = 256-49
x^2 = 207
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x = sqrt(207)
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Cheers,
Stan H.
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