Question 818944
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Hi,
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex
quadratic equation with vertex (3,4) and an x-intercept of (5,0)
{{{y=a(x-3)^2 +4}}} 
{{{0=a(2)^2 +4}}} 
   a = -1
{{{y= -(x-3)^2 +4}}}