Question 67864
{{{pH = -log(10,H)}}}+
{{{pH = -(log(10,2.68*10^(-3)))}}}
{{{pH = -(log(10,2.68) + log(10,10^(-3)))}}}
{{{pH = -(log(10,2.68) + -3*log(10,10))}}}
{{{pH = -(log(10,2.68) - 3)}}}
pH = about 2.5719 very high acidity :P