Question 818819
<pre>

{{{(4h^5-3h^2-9h+1)/(h^2-1)}}}

Put in 0 placeholders for missing (but understood) powers of h: 

{{{(4h^5+0h^4+0h^3-3h^2-9h+1)/(h^2+0h-1)}}}
 thanks :)

       <u>        4h<sup>3</sup>+0h<sup>2</sup>+4h-3</u>  
h<sup>2</sup>+0h-1)4h<sup>5</sup>+0h<sup>4</sup>+0h<sup>3</sup>-3h<sup>2</sup>-9h+1
        <u>4h<sup>5</sup>+0h<sup>4</sup>-4h<sup>3</sup></u>
            0h<sup>4</sup>+4h<sup>3</sup>-3h<sup>2</sup>
            <u>0h<sup>4</sup>+0h<sup>3</sup>+0h<sup>2</sup></u>
                4h<sup>3</sup>-3h<sup>2</sup>-9h
                <u>4h<sup>3</sup>+0h<sup>2</sup>-4h</u>
                   -3h<sup>2</sup>-5h+1
                   <u>-3h<sup>2</sup>+0h+3</u>
                       -5h-2

Answer: 4h3+4h-3+{{{(-5h-2)/(h^2-1)}}}   

Edwin</pre>