Question 818744
{{{10^36}}} is a 1 followed by 36 zeros. To subtract the 63 we have to borrow from the 1 (so it will be gone after subtracting). Then 34 of the 36 zeros will be 9's and the last two digits will be 3 and 7:
<pre>
  1000000000000000000000000000000000000
-                                    63
_______________________________________
   999999999999999999999999999999999937
</pre>So the sum of the digits would be 34*9+3+7 = 306+3+7 = 316.