<PRE><B>Question 69227</B>
   9x + 6       x + 1
----------  *  -------
   3x + 3       6x + 4

==================================
Rewrite as:

=[(9x+6)/(3x+3)] * [(x+1)/(6x+4)]

Factor and cancel to get the following:

=[(3x+2)/(x+1)] * [(x+1)/(2(3x+2)]

Cancel the factors common to the numerator and the denominaor: (3x+2) and (x+1)

= 1/2

Cheers,
Stan H.
</PRE>