Question 818795
solve this equation:
(2*log(x)-8)/(log(x)+2)=log(x)-3
***
let u=log(x)
{{{(2u-8)/(u+2)=u-3}}}
2u-8=(u+2)(u-3)
2u-8=u^2-u-6
u^2-3u+2=0
(u-2)(u-1)=0
..
u=2=log(x)
log(x)=2
x=10^2=100
or
u=1=log)x)
log(x)=1
x=10^1=10