Question 818778
Given:
L1=20
D2=20

Solution:
Area of square = s^2

first square
-
L=20=s
Area = 20^2
Area of 1st square = 400

2nd square: 
D=20 
will create a triangle.
-
{{{D^2 = s^2 + s^2}}}
{{{D^2 = 2s^2 }}}
{{{20^2=2s^2}}}
{{{400=2s^2}}}
{{{ 400/2=2s^2/2}}}
{{{ 200=s^2}}}
{{{ sqrt (200)= sqrt (s^2) }}}
{{{ 10 (sqrt (2))=s}}}

Area = {{{ (10 (sqrt (2))^2)}}}

Area of the 2nd square = 200

Final Solution:

Difference between the Areas = Area of 1st - Area of 2nd

Area = 400 - 200

Area= 200

Final Answer:

the difference between the areas of above two squares is {{{200}}}.